Qualifying Examination

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Solution: By the adjunction formula, the canonical divisor class is KC = OC(d− 3), that is, plane curves of degree d− 3 cut out canonical divisors on C. It follows that if d ≥ 4 then any two points p, q ∈ C impose independent conditions on the canonical series |KC |; that is, h(KC(−p − q)) = g − 2, so by Riemann-Roch h(OC(p+ q)) = 1, i.e., C is not hyperelliptic. Similarly, if d ≥ 5 then any three points p, q, r ∈ C impose independent conditions on the canonical series |KC |; by Riemann-Roch it follows that h(OC(p+ q+ r)) = 1 so C is not trigonal.

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تاریخ انتشار 2015